সৃজনশীলঃ ‘নিচের তথ্যগুলো লক্ষ্য…’ ২০২৪ – পরিবেশ রসায়ন, রসায়ন, রসায়ন ২য় পত্র (এইচএসসি)

$\begin{array}{cc}& \mathrm{PV}=\mathrm{nRT}\\ & \Rightarrow R=\frac{PV}{RT}\\ & n=1\mathrm{mol}\\ & p=1\mathrm{atm}=76\mathrm{em}=1.01396\times {10}^6\mathrm{dyne}/{\mathrm{em}}^2\\ & V=22.10{\mathrm{dm}}^3=22.400{\mathrm{cm}}^3\\ & T=273.1k\\ & \therefore R=\frac{1.01396\times {10}^6\times 22400}{1\times 273.1}\\ & =8.316\times {10}^2\mathrm{eng}{k}^{-1}{\mathrm{mol}}^{-1}\end{array}$

$\begin{array}{cc}{p}_1{v}_1& ={\mathrm{nRT}}_1\\ p_1{v}_1& =\frac{w_1}{m}{\mathrm{Rt}}_1\\ \Rightarrow v_1=& \frac{w_{1}R{T}_1}{m\times p_1}\\ & =\frac{32\times 8.314\times 300}{44\times 1}\\ & =1813.96\\ V_2=\frac{3}{8}{v}_1& =1813.96\times \frac{9}{8}\\ & =80.24\end{array}$

আবার,

$\begin{array}{cc}{p}_2{V}_2=& \frac{w_2}{m}{\mathrm{RT}}_2\\ & \Rightarrow W_1=\frac{p_2{v}_{2}m}{R{T}_2}\\ & =\frac{1\times 680.24\times 44}{8.314\times 400}\\ & =9\end{array}$

বহিষ্কৃত গ্যাসের ভর = w₁ = w₂

                   = 32 – 9

                   = 21 g

x গ্যাসের জন্য,

w₁ = 22g

v₁ = 22.4L

গ্যাসের জন্য,

w₂ = ry

v₂ = 11.2 L

T₁=T₂=25°C= 2981L

ধরি, p₁=p₂=1atm

এখন,

$\begin{array}{cc}& p_1{V}_1=n_1\mathrm{RT}\\ & =\frac{w_1}{m_1}\mathrm{RT}\\ & \Rightarrow m_1=\frac{w_{1}RT}{p_1{v}_1}\\ & =\frac{22\times 0.0821\times 298}{1\times 22.4}\\ & =24.03\\ & m_2==\frac{w_{2}RT}{p_2{v}_2}\\ & =\frac{8\times 0.0821\times 298}{1\times 22.4}=8.74\\ & \frac{rn}{ry}=\sqrt{\frac{m_2}{m_1}}=\sqrt{\frac{8.75}{2403}}=0.6\\ & \therefore \mathrm{ry}>\mathrm{rx}\end{array}$